**10th grade math solution exercise 5.4 part2 :**

Here we are going to see solutions of some problems that we find in the exercise number 5.4

**Question 5 :**

Find the slope and y-intercept of the line whose equation is

(i) y = x + 1

**Solution : **

To find the slope and y-intercept of any line, we have to compare the given equation with y = mx + c.

Here m stands for slope and c stands for y-intercept.

y = x + 1

y = mx + c

By comparing the given equation with general equation, we get slope (m) = 1 and y-intercept c = 1

(ii) 5x = 3y

**Solution :**

3y = 5x

y = (5/3)x

Slope m = 5/3, y-intercept (c) = 0

(iii) 4x - 2y + 1 = 0

**Solution :**

2y = 4x + 1

y = (4/2)x + (1/2)

y = 2 x + (1/2)

Slope m = 2, y-intercept (c) = 1/2

(iv) 10x + 15y + 6= 0

**Solution :**

15y = -10x - 6

y = (-10/15)x - (6/15)

y = (-2/3) x - (2/5)

Slope m = -2/3, y-intercept (c) = 2/5

6. Find the equation of the straight line whose

(i) slope is -4 and passing through (1, 2)

**Solution :**

**Slope (m) = -4 (x**₁,y₁) ==> (1, 2)

(y - y₁) = m (x - x₁)

(y - 2) = -4(x - 1)

y - 2 = -4x + 4

4x + y - 2 - 4 = 0

4x + y - 6 = 0

(ii) slope is 2/3 and passing through (5, -4)

**Solution :**

**Slope (m) = 2/3, (x**₁,y₁) ==> (5, -4)

(y - y₁) = m (x - x₁)

(y - (-4)) = (2/3)(x - 5)

(y + 4) = (2/3) (x - 5)

3(y + 4) = 2(x - 5)

3y + 12 = 2x - 10

2x - 3y - 10 - 12 = 0

2x - 3y - 22 = 0

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