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10th CBSE math solution for exercise 5.3 part 5

(ix) Given a
= 3 , n = 8 ,S n = 192 find d

Solution:

S n = (n/2) [2a + (n - 1) d]

192 = (8/2) [2 (3) + (8 - 1) d]

192 = 4 [6 + 7 d]

192/4 = [6 + 7 d]

48 - 6 = 7 d

42/7 = d

d = 6

(x) Given l
= 28 , S = 144 , and there are total 9 terms. Find a