# 10th CBSE math solution for exercise 5.2 part 3

This page 10th CBSE math solution for exercise 5.2 part 3 is going to provide you solution for every problems that you find in the exercise no 5.2 part 1

## 10th CBSE math solution for exercise 5.2 part 3

(iii) 5, ____ , _____ , 9 ½

Solution:

a = 5     a₄ = 9 ½

= (18 - 1)/2

= 17/2

a + 3 d = 17/2

5 + 3 d = 17/2

3 d = (17/2) - 5

3 d = (17 - 10)/2

3 d = 7/2

d = 7/(2 x 3)

d = 7/6

a= a + d

= 5 + (7/6)

= (30 + 7)/6

= 37/6

a = a + 2 d

= 5 + 2(7/6)

= 5 + (7/3)

= (15 + 7)/3

= 22/3

(iv) -4,____,____,___,_____,6

Solution:

a = -4

a= 6

a + 5 d = 6

-4 + 5 d = 6

5 d = 6 + 4

5 d = 10

d = 10/5

d = 2

Second term = a₂ = a + d

= -4+2

a₂ = -2

Third term a= a + 2 d

= -4+2 (2)

= -4 + 4

a₃ = 0

Fourth term = a + 3 d

= -4+3 (2)

= -4 + 6

a ₄  = 2

Fifth term = a + 4 d

= -2 + 4 (2)

= -2 + 8

= 6

(v) ______,38 , ______ , ______ , ____ , -22

Solution:

a ₂ = 38

a₆ = -22

a + d = 38 --------(1)

a + 5 d = -22 --------(2)

(2) - (1)

a + 5 d = -22

a +  d = 38

(-)   (-)  (-)

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4 d = -60

d = -60/4

d = -15

Substitute d = -15 in the first equation

a + d = 38

a - 15 = 38

a = 38 + 15

a = 53

First term = 53

a ₃ = a + 2d = 53 + 2 (-15) = 23

a ₄ = a + 3d = 53 + 3 (-15) = 8

a ₅ = a + 4d = 53 + 4 (-15) = -7

Therefore first,third,fourth and fifth terms are 53,23,8 and -7 respectively.