# 10th CBSE math solution for exercise 2.2 part 3

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## 10th CBSE math solution for exercise 2.2 part 3

(iv) 1, 1

**Solution:**

α = 1

β = 1

General form of a quadratic
equation

x² – (α + β) x + α β = 0

α + β = 1 + 1

= 2

α β = (1) (1)

= 1

x² – 2 x + 1 = 0

(v) -1/4, 1/4

**Solution:**

α = -1/4

β = 1/4

General form of a quadratic
equation

x² – (α + β) x + α β = 0

α + β = -1/4 + 1/4

= 0

α β = (-1/4) (1/4)

= -1/16

x² – 0 x + (-1/16) = 0

16 x² – 1 = 0

(vi) 4, 1

**Solution:**

α = 4

β = 1

General form of a quadratic
equation

x² – (α + β) x + α β = 0

α + β = 4 + 1

= 5

α β = 4 (1)

= 4

x² – 5 x + 4 = 0

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