SOLVING ONE STEP EQUATIONS WORD PROBLEMS

About "Solving one step equations word problems"

"Solving one step equations word problems" is nothing but the initial stuff of learning how to solve word problems in algebra.

A one-step equation is as straightforward as it sounds. We just have to perform one step in order to solve the equation.

We have to isolate the variable which comes in the equation.

That is, we have to get rid of the number which is added to the variable or subtracted from the variable or multiplied by the variable or divides the variable.

Solving one step equations word problems

Problem 1 :

When 7 is added to a number, we get 25. Find the number.

Solution :

Let "x' be the required number.

According to the question, we have

x + 7  =  25

Here "7" is added to "x". To get rid of 7, we have to subtract 7 on both sides and solve the equation as explained below.

(x + 7) - 7  =  (25) - 7

x  =  18

Hence, the required number is "18".

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Problem 2 :

When we multiply a number by 4, we get 124. Find the number.

Solution :

Let "x' be the required number.

According to the question, we have

4x  =  124

Here "x" is multiplied by "4". To get rid of 4, we have to divide by 4 on both sides and solve the equation as explained below.

4x / 4  =  124 / 4

x  =  31

Hence, the required number is "31".

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Problem 3 :

When we divide a number by 7, we get 14. Find the number.

Solution :

Let "m' be the required number.

According to the question, we have

m / 7  =  14

Here "m" is divided by "7". To get rid of 7, we have to multiply by 7 on both sides and solve the equation as explained below.

(m/7) x 7  =  14 x 7

m  =  98

Hence, the required number is "98".

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Problem 4 :

John had some candies. He gave 5 candies to his friend and now he has 18 candies. How many candies did John initially have ?

Solution :

Let "m' be the no. of candies that John initially had.

According to the question, we have

m - 5   =  18

Here "5" is subtracted from "m". To get rid of 5, we have to add 5 on both sides and solve the equation as explained below.

(m - 5) + 5  =  18 + 5

m  =  23

Hence, John initially had 23 candies.

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Problem 5 :

Alex borrowed some money from Jose. After 3 years, Alex returned 2 times of borrowed money to Jose. If the returned money is \$226, how much money did Alex borrow from Jose ?

Solution :

Let "x' be the borrowed money.

According to the question, we have

2x   =  226

Here "x" is multiplied by 2. To get rid of 2, we have to divide by 2 on both sides and solve the equation as explained below.

2x / 2  =  226 / 2

x  =  113

Hence, the borrowed money is \$113.

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Problem 6 :

The sum of two numbers 22.5. If one number is 7.5, find the other number.

Solution :

Let "x' be the other number.

According to the question, we have

x + 7.5   =  22.5

Here "7.5" is added to "x". To get rid of 7.5, we have to subtract 7.5 on both sides and solve the equation as explained below.

(x + 7.5) - 7.5  =  22.5 - 7.5

x  =  15

Hence, the other number is 15.

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Problem 7 :

David has some money. He gave one fourth of the money to Lily. If Lily gets \$8 from David, how much money did David have initially ?

Solution :

Let "m' be the money that David had initially.

According to the question, we have

m / 4  =  32

Here "m" is divided by "4". To get rid of 4, we have to multiply by 4 on both sides and solve the equation as explained below.

m/4 x 4  =  32 x 4

m  =  128

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Problem 8 :

In a deposit, invested money will become 4 times itself in 5 years. If Rosy receives \$3280 after five years, how much money did Rosy invest ?

Solution :

Let "m' be the money that Rosy invested.

According to the question, we have

4m  =  3280

Here "m" is multiplied by "4". To get rid of 4, we have to divide by 4 on both sides and solve the equation as explained below.

4m / 4   =  3280 / 4

m  =  820

Hence, Rosy invested \$820.

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Problem 9 :

Jacob has some number of candies and Michael has 35 candies. If Michael has candies 5 times as Jacob, how many candies does Jacob have ?

Solution :

Let "p' be the number of candies that Jacob has.

According to the question, we have

5p  =  35

Here "p" is multiplied by "5". To get rid of 5, we have to divide by 5 on both sides and solve the equation as explained below.

5p / 5   =  35 / 5

p  =  7

Hence, Jacob has 5 candies.

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Problem 10 :

Daniel had some hot dogs and he gave one third of the hot dogs to Alex. If Alex gets 8 hot dogs from Daniel, how many hot dogs did have initially ?

Solution :

Let "h" be the number of hot dogs that Daniel had initially.

According to the question, we have

m / 3  =  8

Here "m" is divided by "3". To get rid of 3, we have to multiply by 3 on both sides and solve the equation as explained below.

m/3 x 3  =  8 x 3

m  =  24

Hence, Daniel had 24 hot dogs initially.

Solving one step equations - Worksheets

Worksheet -1

Worksheet -2

Worksheet -3

Worksheet -4

Worksheet -5

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