Solution of Digit Problem1





In this page solution of digit problem1 we are going to see solution for question 1 and question 2 with detailed steps.

Question 1:

The sum of digits of a two digit numbers is 15 and if 9 is added to the number the digits are interchanged. Find the required number.

Solution:

Let "x y" be the required two digit number. Here "x" is in ten's place and "y" is in unit place

The sum of digits of a two digit number  = 15

                                              x + y = 15  ------(1)

If 9 is added to the number the digits are interchanged

                                 x y + 9 = y x

Now let us write this number in expanded form

                          10 x + y + 9 = 10y + x

                   10 x - x + y - 10 y = -9

                                   9x - 9y = -9      ------(2)

By solving these two equations we will get the value of x and y.

      (1) x 9 => 9 x + 9 y = 135

      (1) + (2)   9 x - 9 y = -9

                   ______________

                     18 x = 126

                         x = 126/18

                         x = 7

Substituting x = 7 in first equation 

                      7 + y = 15

                           y = 15 - 7

                           y = 8

Therefore the required number is 78


Checking:

The sum of digits of a two digit number is 15.

Answer 78 is satisfying this condition. Because 7 + 8 = 15

If 9 is added to the number the digits are interchanged

That is 78 + 9 = 87



Question 2:

The sum of the digits of a two digit number is 10. If the number formed by reversing the digits is less than the original number by 36,find the required number.

Solution:

Let "x y" be the required two digit number. Here "x" is in ten's place and "y" is in unit place.

The sum of the digits of a two digit number = 10

                                                   x + y = 10  --------(1)

If the number formed by reversing the digits is less than the original number by 36.

                                y x = x y - 36

Let us write these as expanded form

                         10 y + x = 10 x + y - 36

           x - 10 x + 10 y - y = - 36

                      - 9 x + 9 y = - 36

By divide this equation by 9 we will get

                            - x + y = -4  --------(2)


  (1) + (2)                x + y = 10

                           - x + y = -4

                           ___________

                                  2 y = 6

                                     y = 6/2

                                     y = 3

Substituting y = 3 in the first equation

                       x + 3 = 10

                             x = 10 - 3

                             x = 7

Therefore the required number is 73.


Checking:

The sum of digits of a two digit number is 10.

Answer 73 is satisfying this condition. Because 7 + 3 = 10

If the number formed by reversing the digits is less than the original number by 36.

That is 37 = 73 - 36 solution of digit problem1

These are the problems in solution of digit problem1.







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