This page samacheer kalvi math solution for exercise 3.15 part2 is going to provide you solution for every problems that you find in the exercise no 3.15
(v) x² - ( √3 + 1) x + √3 = 0
Solution:
x = -1 , -√3
(2) Solve the following quadratic equations using quadratic formula
(i) x²- 7x + 12 = 0
Solution:
a = 1 b = -7 c = 12
= 8/2, 6/2
= 4, 3
(ii) 15x²- 11 x + 2 = 0
Solution:
a = 15 b = - 11 c = 2
= 12/30 , 10/30
= 2/5 , 1/3
In the page samacheer kalvi math solution for exercise 3.15 part1 we are going to see the solution of next problem
(iii) x + (1/x) = 2 ½
Solution:
(x² + 1)/x = 5/2
2 (x² + 1) = 5 x
2 x² + 2 = 5 x
2 x² - 5 x + 2 = 0
a = 2 b = -5 c = 2
x = 8/4 , 2/4
x = 2 , 1/2
(iv) 3 a²x² - ab x - 2b² = 0
a = 3 a² b = - ab c = - 2b²
x = 6ab/6a² , -4ab/6a²
x = b/a , x = -2b/a
(v) a (x² + 1) = x(a² + 1)
Solution:
a x² + a = x(a² + 1)
a x² - x(a² + 1) + a = 0
a = a b = -(a² + 1) c = a
x = 2a²/2a , 2/2a
= a , 1/a
(vi) 36 x² - 12 a x + (a² - b²) = 0
a = 36 b = -12 a c = (a² - b²)
x = (a + b)/6 , (a - b)/6
(vii) [(x - 1)/(x + 1)] + [(x - 3)/(x - 4)] = 10/3
Solution:
[(x - 1)(x - 4) + (x - 3)(x + 1)]/(x + 1)(x- 4) = 10/3
(x² - 5 x + 4 + x² - 2 x - 3)/(x² - 3 x - 4) = 10/3
3 (2x² - 7 x + 1) = 10(x² - 3 x - 4)
10 x² - 6 x² - 30 x + 21 x - 40 - 3 = 0
4 x² - 9 x - 43 = 0
(viii) a² x² + (a²- b²)x - b²= 0
Solution:
a = a² b = (a²- b²) c = - b²
x = 2b²/2a², -2a²/2a²
x = b²/a² , -1
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