Question1 and 2





In this page question1 and 2 we are going to see solution for question 1 and 2.

Question 1:

Martin is four times as old as his brother Luther at present. After 10 years he will be twice the age of his brother. Find their present ages.

Solution

Let "X" be the present age of Luther

Martin's age = 4 x Luther's age

Martin's age = 4 X

After 10 years the age of Luther will be (x + 10) and the age of Martin will be 4x + 10.

then

                     4 x + 10 = 2 (x + 10)

                     4 x + 10 = 2 x + 20

                      4x - 2x =  20 - 10            

                             2x = 10

                               x = 5 

Age of Luther = 5 years

Age of Martin = 4 x 5

                    =  20 years

So the correct option is (B) 5 years and 20 years



Question 2:

A father is 30 years older than his son,and one year ago he was four times as old as his son. Find the present ages of  his father and his son.

Solution

Let "X" be the son's present age

Father's present age = x + 30

One year ago son's age = x - 1                            

One year ago father's age = x + 30 - 1

                                     = x + 29

father's age = 4 x age of son

      x + 29 = 4 (x-1)                     

      x + 29 = 4x - 4

       x - 4x = - 4 - 29

          - 3x = -33  

              x = 33/3

              x = 11

Present age of son = 11 years

present age of father = x + 30

                               = 11 + 30         

                               = 41 years

So the correct option is (A) 11 years and 41 years                         





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