Probability Worksheet Solution1





In this page probability worksheet solution1 we are going to see solution of some practice questions of the probability worksheet.

Question 1

A ticket is drawn from bag containing 100 tickets. The tickets are numbered from one to hundred. What is the probability of getting a ticket with a number divisible by 10?

Solution:

The tickets are numbered from one to hundred

Sample space S = {1 , 2 , 3 , 4 , ……………………. 100}

                    n(s) = 100             

Let A be the event of getting a ticket with a number divisible by 10

A = {10,20,30,40,50,60,70,80,90,100}

n(A) = 10

Probability of getting a ticket with a number divisible by 10

P(A) = n(A)/n(S)

          = 10/100    

          = 1/10

Therefore the probability of getting a ticket with a number divisible by 10 is 1/10


Question 2

A die is thrown twice. Find the probability of getting a total of 9.

Solution:

A dice is thrown twice

Sample space S = { (1,1),(1,2),(1,3),(1,4) ,(1,5), (1,6)

                             (2,1),(2,2),(2,3),(2,4) ,(2,5), (2,6)

                             (3,1),(3,2),(3,3),(3,4),(3,5), (3,6)

                             (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)                                 

                             (5,1),(5,2),(5,3),(5,4) ,(5,5), (5,6)

                            (6,1),(6,2),(6,3),(6,4) ,(6,5), (6,6)}

                       n(S) = 36

Let A be the event of getting a total of 9

A = {(3,6), (4,5), (5,4), (6,3)}

n(A) = 4

Probability of getting a total of 9 P(A) = n(A)/n(S)

                                                      = 4/36

                                                     = 1/9

Therefore the probability of getting a total of 9 is 1/9


Question 3

Two dice re thrown together. Find the probability that two digits number formed with two numbers turning up is divisible by 3.

Solution:

Two dice are thrown together

Sample space S = { (1,1),(1,2),(1,3),(1,4) ,(1,5), (1,6)

                             (2,1),(2,2),(2,3),(2,4) ,(2,5), (2,6)

                             (3,1),(3,2),(3,3),(3,4),(3,5), (3,6)

                             (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)                                 

                             (5,1),(5,2),(5,3),(5,4) ,(5,5), (5,6)

                            (6,1),(6,2),(6,3),(6,4) ,(6,5), (6,6)}

                       n(S) = 36

Let A be the event of getting two digits number formed with two numbers turning up is divisible by 3.

A = {(1,2), (1,5), (2,1), (2,4) , (3,3) , (3,6) , (4,2) , (4,5) , (5,1) , (5,4) , (6,3) , (6,6)}

n(A) = 12

Probability of getting A , P(A) = n(A)/n(S)

                                           = 12/36

                                          = 1/3

Therefore the probability that two digits number formed with two numbers turning up is divisible by 3 is 1/3

probability worksheet solution1 probability worksheet solution1