The set of all subsets of A is said to be the power set of the set A.
Reading Notation :
The power set of A is denoted by P(A).
Example 1 :
Let A = {1, 2, 3}. Find the power set of A.
Solution :
We know that the power set is the set of all subsets.
Here, the given set A contains 3 elements.
Then, the number of subsets = 23 = 8.
Therefore,
P(A) = {{1}, {2}, {3}, {1, 2}, {2, 3}, {1, 3}, {1, 2, 3}, { }}
Example 2 :
Let A = {a, b, c, d, e} find the cardinality of power set of A.
Solution :
The formula for cardinality of power set of A is given below.
n[P(A)] = 2n
Here 'n' stands for the number of elements contained by the given set A.
The given set A contains five elements. So n = 5.
Then, we have
n[P(A)] = 25
n[P(A)] = 32
The cardinality of the power set of A is 32.
A set X is a subset of set Y if every element of X is also an element of Y.
In symbol we write
x ⊆ y
Reading Notation :
Read ⊆ as "X is a subset of Y" or "X is contained in Y"
Read ⊈ as "X is a not subset of Y" or "X is not contained in Y"
A set X is said to be a proper subset of set Y if X ⊆ Y and X ≠ Y.
In symbol, we write X ⊂ Y.
Reading Notation :
Read X ⊂ Y as "X is proper subset of Y".
The figure given below illustrates this.
A set X is said to be a proper subset of set Y if X ⊆ Y and X ≠ Y.
In symbol, we write X ⊂ Y
Here,
Y is called super set of X
If A is the given set and it contains n number of elements, we can use the following formula to find the number of subsets.
Number of subsets = 2n
Formula to find the number of proper subsets :
Number of proper subsets = 2n - 1
We already know that the set of all subsets of A is said to be the power set of the set A and it is denoted by P(A).
If A contains n number of elements, then the formula for cardinality of power set of A is
n[P(A)] = 2n
Note :
Cardinality of power set of A and the number of subsets of A are same.
Null set is a proper subset for any set which contains at least one element.
For example, let us consider the set A = {1}.
It has two subsets. They are { } and {1}.
Here null set is proper subset of A. Because null set is not equal to A.
If null set is a super set, then it has only one subset. That is { }.
More clearly, null set is the only subset to itself. But it is not a proper subset.
Because, { } = { }.
Therefore, A set which contains only one subset is called null set.
List the elements of the set A, which is the set of all:
Problem 1 :
positive whole numbers between 5 and 10
Solution :
A = {6, 7, 8, 9}
Problem 2 :
odd numbers between 10 and 20
Solution :
A = {11, 13, 15, 17, 19}
Problem 3 :
months of the year
Solution :
A = {January, February, March, April, May, June, July, August, September, October, November, December}
Problem 4 :
factors of 30
Solution :
A = {1, 2, 3, 5, 6, 10, 15, 30}
Problem 5 :
planets of the solar system
Solution :
A = {Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune}
Problem 6 :
letters which make up the word BASEBALL
Solution :
A = {B, A, S, E, L}
Problem 7 :
colours of keys on a piano
Solution :
A = {C, D, E, F, G, A, B}
Problem 8 :
square numbers between 50 and 60.
Solution :
There is no square number in between 50 and 60. Then there must be a null set.
A = { }
Problem 9 :
Find n(A) for each of the sets
Let P = {1, 5, 7, 8, 10} and Q = {1, 4, 5, 8, 9, 10}.
Find
i) n(P) ii) n(Q)
Solution :
P = {1, 5, 7, 8, 10} and Q = {1, 4, 5, 8, 9, 10}.
Number of elements in the set P is 5
n(P) = 5
Number of elements in set Q is 6
n(Q) = 6
Problem 10 :
List all the subsets of {w, x, y, z}
Solution :
{w, x, y, z}
Subsets are,
{ }, {w}, {x}, {y}, {z}, {w, x}, {w, y}, {w, z}, {x, y}, {x, z}, {y, z}, {w, x, y}, {w, y, z}, {w, z, x}, {x, y, z}, {w, x, y, z}
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