We are going to see some important examples in this page 'Limits-examples'.

Example1:

Find the limit ₓ→∞ x/x+1

Solution:

The given sequence is 1/2,2/3, 3/4, 4/5, .....999/1000, ...

As the number going on increasing, that is the value of x is increasing the value of the terms approaches 1. So the value of the limit is **1**.

Example 2:

Find the limit as x approaches 0 of (sin x)/x.

Solution:

We can not directly substitute the value of x as 0 because

sin 0 /0 is identified. We can substitute values of x which is closer to 0 and we can finally conclude that

limit ₓ→₀ (sin x)/x = 1.

We will see some types of evaluating the limit problems in the page 'Limits-examples'.

Type I:

__Solving limit problems by direct substitution:__

1. Evaluate the limit as x tends to a of x².

Solution: Lim ₓ→ₐ x² = a².

(Here we had substitute the value of x as a).

2. Evaluate the limit as x tends to 3 of (x²-10).

Solution: Lim x→₃ (x²-10).

= (3² -10)

= 9 - 10

= -1

Type 2:

__Solving Limit problems by factoring__:

1. Evaluate the limit as x tends to 1 of (x²-1)/(x-1)

Solution:

If we directly apply as x approaches 1, then we will have 0/0. But if we factorize the given function, then we will get the limit.

Let us factorize

(x²-1)/(x-1) = (x-1)(x+1)/(x-1)

= x+1

Now applying the limit as x tends to 1, then we will get the answer

= 1+1 =2

2. Evaluate the limit as x approaches 2 of (x²+x-6)/(x²-2x).

Solution:

In this problem also if we apply the limit directly, then the whole problem will become as 0/0. So let us factorize the numerator and denominator.

(x²+x-6)/(x²-2x) = [(x+3)(x-2)]/ x(x-2)

= (x+3)/ x

Substituting the value of x as 2, we get the value as 5/2.

Type 3:

__Solving limit problems by rationalizing the numerator:__

1. Evaluate the limit :

Solution:

In this problem we have to rationalize the numerator by multiplying the conjugate of the numerator.

= [x - √(3x+4)][x+√(3x+4)]/(4-x)[x+√(3x+4)]

= x² -(3x+4)/(4-x)[x+√(3x+4)]

= x²-3x -4 / (4-x)[x+√(3x+4)]

Now factorize the numerator

= (x-4)(x+1)/(4-x)[x+√(3x+4)]

= (x+1)/ {-[x+√(3x+4)]}

Now applying the limit as x tends to 4, we get the value as

= (4+1)/{-[[4+√(3(4)+4))]}

= -5/8.

Students can try to solve the problem on their own, they can verify the steps with the steps discussed in 'Limits-examples' . If you are having any doubt you can contact us through mail, we will help you to clear your doubts.

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