In this page lcm practical problems question1 we are going to see solution of first problem.

**Question 1:**

Henry walks 60 cm in one step and Rahim walks 75 cm in one step. Determine the shortest that either of them can measure by an exact number of steps. How many steps will each take to cover that distance?

**Solution:**

Henry is covering 60 cm for each step of his walking. Rahim is covering 75 cm for each step of his walking. From this we need to find the shortest that either of them can measure by an exact number of steps. For that we have to take L.C.M Otherwise we can write 60 times table and 75 times table separately and find out which least number we got. Since this is the lengthy method we are going to choose the first method. That is taking L.C.M

60 = 5 x 2 x 2 x 3

75 = 5 x 5 x 3

= 5 x 5 x 2 x 2 x 3

L.C.M = 300

So the required shortest distance covered by Henry and Rahim is 300 cm

Now we have to find how many steps that Henry is taking to cover the distance of 300 cm. For that we are going to divide 300 by measurement of 1 step by Henry.

Number of steps taken by Henry = 300/60

= 5

Number of steps taken by Rahim = 300/75

= 4

lcm practical problems question1 lcm

**Synthetic division****Rational Expressions****Rational Zeros Theorem****LCM -Least Common Multiple****GCF-Greatest Common Factor****Simplifying Rational Expressions****Factorize of Polynomials****Factoring Worksheets****Framing Quadratic Equation From Roots****Framing Quadratic Equation Worksheet****Remainder Theorem****Relationship Between Coefficients and roots****Roots of Polynomial of Degree4****Roots of Polynomial of Degree5****System Of Linear Equations**