In this page decimal word problems you can find 17 questions given in the form of test paper.If you have any doubts in this problem you can look in to the solution.Here is the first question
Question 1:
A chemist mixed 6.35 grams of one compound with 2.45 grams of another compound. How many grams were there in the mixture.
Question 2:
What is the total cost of these items.Pen $10.50,books $25.75,bag $ 45.50
Question 3:
John wants to buy a bicycle that cost $ 450.75. He has saved $ 125.35.How much more money must John save in order to have enough money to buy the bicycle?
Question 4:
Jennifer bought 6.5 kg of sugar. she used 3.75 kg. How many kilograms of sugar were left?
Question 5:
The inner diameter of a pipe is 25.25 mm. The outer diameter is 36.05 mm.What is the difference in the diameter?
Question 6:
A map is 1.3 m long and 0.8 m wide. Find its area.
Question 7:
A copy of English book weighs 0.45 kg. What is the weight of 20 copies?
Question 8:
Find the weight of 25.5 meters of copper wire. If one meter weighs 10.5 grams.
Question 9:
Mars takes 1.88 years to travel around the Sun. How long will mars take to go around the sun 100 times.
Question 10:
A square lawn is 12.25 m long.Find the perimeter.
Question 11:
A ream of paper weighs 2.05 kg. What is the weight of 35 reams?
Question 12:
Robert paid $140 for 2.8 kg of cooking oil. How much did 1 kg of the cooking oil cost?
Question 13:
Joseph earned $20.70 for working 6 hours. How much was he paid for an hour?
Question 14:
John hiked 9.6 miles in 3 hours.How many miles an hour did he hike?
Question 15:
Divide $ 58.53 equally among 4 people. How much does each person getting?
Question 16:
A wire measures 0.12 meters. If you cut it into 3 pieces of equal length, how much long will each piece be?
Question 17:
A pipe is 76.8 meters long. What will the greatest number of pieces of pipe each 8 meters long that can be cut from this pipe?
These are the question in the topic decimal word problems.
Solution for question 1 |
Quantity of one compound = 6.35 grams
Quantity of another compound = 2.45 grams Total quantity of mixture = Quantity of one compound + quantity of another compound = 6.35 + 2.45 = 8.8 grams |
Step 1:
In this problem a chemist is mixing 6.35 grams of one compound with 2.45 grams of another compound. Step 2: From this we need to find number of grams were there in the mixture. Step 3: To solve this problem we have to add both the measurements of two compounds. |
Solution for question 2 |
Cost of pen = $10.50
Cost of books = $25.75 Cost of bag = $ 45.50 Total cost = Cost of pen + Cost of books + Cost of bag = $10.50 + $25.75 + $ 45.50 = $ 81.75 |
Step 1:
In this problem we have cost of three items.And we need to find the total cost of these items. Step 2: To solve this problem we have to apply the concept addition. Step 3: We have to add all the three cost to get the total cost. |
Solution for question 3 |
Cost of a bicycle = $ 450.75
Money that he saved = $ 125.35 Difference of money = cost of bicycle - money that he saved = $ 450.75 - $ 125.35 450.75 125.35 -------- 325.40 -------- = $ 325.40 Therefore $ 325.40 money must John save in order to have enough money to buy the bicycle |
Step 1:
In this problem John wants to buy a bicycle which costs $ 450.75 and he saved $ 125.35. Step 2: Now we need to find how much money must John save in order to have enough money to buy the bicycle. Step 3: To solve this problem we have to use the concept subtraction. Step 4: To find the difference we have to subtract 125.35 from 450.75. |
Solution for question 4 |
Quantity of sugar that Jennifer had = 6.5 kg
Quantity of sugar that Jennifer used = 3.75 kg Remaining quantity of sugar = Original quantity of sugar - used sugar = 6.5 - 3.75 6.50 3.75 -------- 2.75 -------- Therefore the remaining quantity of sugar = 2.75 kg |
Step 1:
In this problem Jennifer is buying 6.5 kg of sugar and she has used 3.75 kg of sugar. Step 2: Now we have to find how much of sugar does Jennifer has Step 3: To solve this problem we have to use the concept subtraction. Step 4: To find the remaining quantity we have to subtract the used quantity of sugar from the original quantity of sugar. |
Solution for question 5 |
The inner diameter of a pipe = 25.25 mm
The outer diameter of the pipe = 36.05 mm Difference in the diameter = Outer diameter - inner diameter = 36.05 -25.25 = 10.80 mm Therefore difference in diameter = 10.80 mm |
Step 1:
In this problem We have two diameters inner diameter and outer diameter. Step 2: Probably the outer diameter will be more than the inner diameter. Step 3: Now we need to find the difference in diameters. Step 4: To solve this problem we have to apply the concept subtraction.We need to subtract outer diameter from inner diameter. |
Solution for question 6 |
Length of the map = 1.3 m
Width of the map = 0.8 m Area of the map = Length x width = 1.3 x 0.8 = 1.04 square meter Therefore area of the map is 1.04 square meter. |
Step 1:
In this problem a map is having the measurements 1.3 m as length and 0.8 m as width. Step 2: Now we have to find the area. For that we have to use the formal for rectangle. Step 3: Here length (L) is 1.3 m and width (w) is 0.8 m and the the formula to find area of the triangle is l x w. |
Solution for question 7 |
Weight of English book = 0.45 kg
The weight of 20 copies = Weight of one book x 20
= 0.45 x 20
= 9 kg Therefore the weight of 20 books is 9 kg |
Step 1:
In this problem we have the weight of one English book and we need to find the weight of 20 copies like this. Step 2: To solve this problem we have to use the concept multiplication. Step 3: We have to multiply the weight of one book with 20 to get weight of 20 books. |
Solution for question 8 |
Weight of 1 meter copper wire = 10.5 grams
The weight of 25.5 meters = 25.5 x 10.5 = 267.75 grams So the weight of 25.5 meter copper wire is 267.75 grams. |
Step 1:
In this problem we have a copper wire having the length 25.5 meters. Step 2: If the weigh of one meter is 10.5 grams then we have to find the weight of 25.5 meter. Step 3: To solve this problem we have to use the concept multiplication. Step 4: For that we have to multiply 25.5 with 10.5. |
Solution for question 9 |
Time taken by Mars to travel around the Sun = 1.88 years
Time taken by Mars to travel around the Sun 100 times = 1.88 x 100 = 188 years |
Step 1:
In this problem Mars is taking 1.88 years to travel around the sun. Step 2: Now we need to find how long will mars take to go around the sun 100 times. Step 3: To solve this problem we have to use the concept multiplication. Step 4: We have to multiply the time taken by mars to travel around the sun by 100. |
Solution for question 10 |
Side length of the square = 12.25 m
Perimeter of the square = 4a Here a = 12.25 m = 4 (12.25) = 49 m Therefore the perimeter of the square is 49 m. |
Step 1:
In this problem we know the length of one side of the shape square and we need to find the perimeter of square. Step 2: To solve this problem we have to apply the formula to find the perimeter of the square that is 4a. Step 3: Here a represents side length of the square. |
Solution for question 11 |
The weight of 1 ream of paper = 2.05 kg
Weight of 35 reams = Weight of one ream x 35 = 2.05 x 35 = 71.5 kg Weight of 35 reams = 71.5 kg |
Step 1:
In this problem a ream of paper weighs 2.05 kg. Step 2: Now we need to find the cost of 35 reams. Step 3: To solve this problem we have to use the concept multiplication. Step 4: We have to multiply 2.05 with 35 to get the final answer. |
Solution for question 12 |
Cost of 2.8 kg of cooking oil = $ 140
Cost of 1 kg of cooking oil = 140 ÷ 2.8 = (140/2.8) x (10/10) = 1400/28 = $ 50 Therefore the cost of 1 kg = $50 |
Step 1:
In this problem Robert paid $140 for 2.8 kg of cooking oil. Step 2: We need to find that how much did 1 kg of the cooking oil cost. Step 3: .To solve this problem we have to use the concept division. Step 4: We divide cost $ 140 by 2.8.So that we will get the answer for cost of 1 kg. |
Solution for question 13 |
Money earned for working 6 hours = $ 20.70
Money earned for working an hour = $ 20.70 ÷ 6 = (20.70/6) x (100/100) = 2070/600 = $ 3.45 He will be paid $ 3.45 per hour. |
Step 1:
In this problem Joseph had earned $20.70 for working 6 hours. Step 2: We need to find how much he will be paid for an hour. Step 3: To solve this problem we have to use the concept division. Step 4: We have to divide cost for working 6 hours divided by 6. |
Solution for question 14 |
Number of miles hiked by John in 3 hours = 9.6 miles
Number of miles hiked by John in an hour = 9.6 ÷ 3 = (9.6/3) x (10/10) = 96/30 = 16/5 = 3.2 miles |
Step 1:
In this problem John hiked 9.6 miles in 3 hours. Step 2: Now we need to find how many miles an hour he will hike. Step 3: .To solve this problem we have to divide 9.6 miles by 3 hours. |
Solution for question 15 |
Original amount to be divided to four people = $ 58.56
Provided amount for 1 person = 58.56 ÷ 4 = (58.56/4) x (100/100) = 5856/400 = $ 14.64 |
Step 1:
In this problem, we have to divide $ 58.53 equally among 4 people. Step 2: To solve this problem we have to use the concept division. Step 3: We have to divide 58.53 by 4. |
Solution for question 16 |
The original measurement of the wire = 0.12 meters
No of of pieces to be cut = 3 length of each piece = 0.12 ÷ 3 = (0.12/3) x (100/100) = 12/300 = 0.04 meter Therefore the length of each piece is 0.04 meter. |
Step 1:
In this problem a wire is having the length 0.12 meter. Step 2: In this problem a wire is having the length 0.12 meter. Step 3: From this we have to find the length of each piece. Step 4: For that we have to use the division concept. |
Solution for question 17 |
The original length of the pipe = 76.8 meters
The length of each pipe piece = 8 meter No of pieces which had been cut = 76.8 ÷ 8 = (76.8/8) x (10/10) = 768/80 = 9.6 So we will get 9 pieces. |
Step 1:
In this problem a pipe is measuring 76.8 meter long and this pipe is going to cut into 8 meter long Step 2: Now we need to find how many pieces we will get. Step 3: To solve this problem we have to divide 76.8 by the length of one piece. |