Question 1 :
A solid right circular cylinder has radius of 14 cm and height of 8 cm. Find its curved surface area and total surface area.
Solution :
Radius of the cylinder (r) = 14 cm
Height of the cylinder (h) = 8 cm
Curved surface area of cylinder = 2 Π r h
= 2 ⋅ (22/7) ⋅ 14 ⋅ 8
= 2 ⋅ 22 ⋅ 2 ⋅ 8
= 704 sq.cm
Total surface area of cylinder = 2 Π r (h + r)
= 2 ⋅ (22/7) ⋅ 14 ⋅ (8 + 14)
= 2 ⋅ (22/7) ⋅ 14 ⋅ 22
= 2 ⋅ 22 ⋅ 2 ⋅ 22
= 1936 sq.cm
Curved surface area = 704 sq.cm
Total surface area = 1936 sq.cm
Question 2 :
The total surface area of a solid circular is 660 sq.m If its diameter of the base is 14 cm. Find the height and curved surface area of the cylinder.
Solution :
Radius of the cylinder = 14/2 = 7 cm
Total surface area of cylinder = 660 sq.m
2 Π r (h + r) = 660 sq.m
2 ⋅ (22/7) ⋅ 7 ⋅ (h + 7) = 660
h + 7 = 660 ⋅ (1/2) ⋅ (7/22) ⋅ (1/7)
h + 7 = 15
h = 8 cm
Curved surface area of cylinder = 2 Π r h
= 2 ⋅ (22/7) ⋅ 7⋅ 8
= 352 Sq.cm
Height = 8 cm
Curved surface area = 352 sq.cm
Question 3 :
Curved surface area and circumference at the base of a solid right circular cylinder are 4400 sq.cm and 110 cm respectively. Find its height and diameter.
Solution:
Curved surface area of cylinder = 4400 sq.cm
Circumference of the base = 110 cm
2 Π r = 110
2 ⋅ (22/7) ⋅ r = 110
r = 110 ⋅ (1/2) ⋅ (7/22)
r = 17.5 cm
diameter = 2 r
= 2 (17.5)
= 35 cm
2 Π r h = 4400
110 ⋅ h = 4400
h = 4400/110
h = 40 cm
Height = 40 cm
Diameter of the cylinder = 35 cm
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