SOLVING LINEAR EQUATIONS USING CROSS MULTIPLICATION METHOD

This is one of the methods we use to solve system of linear equations.

Let us consider the following system of linear equations. 

a1x + b1y + c1  =  0

a2x + b2y + c2  =  0

We have to write the coefficients of the equations and do cross multiplication as shown below. 

We write the coefficient of y and constant term and two more columns by repeating the coefficients of x and y as follows. 

The result is given by

The solution is

Solve the following system of equations using cross multiplication method.

(i)   3x + 4y = 24, 20x - 11y = 47

(ii)  0.5x + 0.8y = 0.44 , 0.8x + 0.6y = 0.5

(iii) (3x/2) - (5y/3) = -2 , (x/3) + (y/2) = 13/6

(iv) (5/x)-(4/y)  =  -2 , (2/x)+(3/y)  =  13

Detailed Solution

(i)   3x + 4y  =  24, 20x - 11y  =  47

Solution :

3x + 4y - 24 = 0    ----- (1)

20x - 11y - 47 = 0 ----- (2)

x/(-188-264)  = y/(-480 -(-141))   = 1/(-33-80)

x/(-452)  = y/(-480+141))   = 1/(-33-80)

x/(-452)  = y/(-339)   = 1/(-113)

x/(-452)  =  1/(-113)

x  =  (-452)/(-113)

x  =  4

y/(-339)  =  1/(-113) 

y  =  (-339)/(-113)

y  =  3

So, the solution is (4, 3).

(ii)  0.5x + 0.8y = 0.44 , 0.8x + 0.6y = 0.5

Solution :

0.5x+0.8y  =  0.44  ----- (1)

0.8x+0.6y  =  0.5  ----- (2)

To make the decimal numbers into integers, we have to multiply the first equation by 100 and the second equation by 10.

50x+80y-44  =  0 ----- (1)

8x+6y-5  =  0  ----- (2)

x/(-400-(-264))  =  y/(-352 -(-250))  =  1/(300-640)

x/(-400+264)   =  y/(-352+250))  =  1/(-340)

x/(-136)  =  y/(-102)  =  1/(-340)

x/(-136)  =  1/(-340)

x  =  (-136)/(-340)

x  =  0.4

y/(-102)  =  1/(-340) 

y  =  (-102)/(-340)

y  =  0.3

So, the solution is (0.4, 0.3).

(iii) (3x/2) - (5y/3) = -2 , (x/3) + (y/2) = 13/6

Solution :

9x - 10y  =  -12

(2x + 3y)/6  =  13/6

9x-10y+12  =  0 ----- (1)

2x+3y-13  =  0 ----- (2)

x/(130-36)  =  y/(24 -(-117))  =  1/(27-(-20))

x/(94)  =  y/(24+117))  =  1/(27+20)

x/(94)  =  y/(141)  =  1/(47)

x/(94)  =  1/(47)

x  =  94/47

x  =  2

y/(141)  =  1/(47) 

y  =  (141)/(47)

y  =  3

So, the solution is (2, 3).

(iv) (5/x)-(4/y)  =  -2 , (2/x)+(3/y)  =  13

Solution :

Let 1/x = a and 1/y = b

5a-4b  =  - 2   

2a+3 b  =  13   

5a - 4b + 2 = 0   ----- (1)

2a + 3b - 13 = 0  ----- (2)

a/(52-6)  =  b/(4 -(-65))   =  1/(15-(-8))

a/46  =  b/(4 +65)   =  1/(15+8)

a/(46)   =  b/(69)   =  1/(23)

a/(46)   =  1/(23)

a  =  46/23

 a  =  2

b/(69)   =  1/(23) 

b  =  69/23

b = 3

x  =  1/2 and y  =  1/3

So, the solution is (1/2, 1/3).

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