Combination of Solids Solution11





In this page combination of solids solution11 we are going to see solution some practice questions of the worksheet combination of solid worksheet2.

Question 11:

A spherical solid material of radius 18 cm is melted and recast in to three small solid spherical spheres of different sizes. If the radii of two spheres are 2 cm and 12 cm,find the radius of new solid.

Solution:

Volume of sphere = (4/3) Π r³

(4/3) Π (18)³  = (4/3) Π (2)³  + (4/3) Π (12)³  + (4/3) Π r³                        

(4/3) Π (18)³  = (4/3) Π [(2)³ + (12)³ + r³ ]

(18)³  = [(2)³ + (12)³ + r³ ]

5832 = 8 + 1728 +

5832 = 1736 +

5832 - 1736 =

4096 =

 r = ∛16 x 16 x 16

 r = 16 cm

Radius of third sphere = 16 cm

combination of solids solution11 combination of solids solution11