HOW TO FIND THE CENTER AND RADIUS OF A CIRCLE FROM ITS EQUATION

Equation of a circle in standard form with center (0, 0) and radius 'r'.

x2 + y2  =  r2

Equation of a circle in standard form with center (h, k) and radius 'r'.

(x - h)2 + (y - k)2  =  r2

Equation of a circle in general form :

x2 + y2 + 2gx + 2fy + c = 0

where the center is (-g, if) and radius is √(g2 + f2 - c).

Find the center and radius of the following circles.

Example 1 :

x2 + y2 = 25

Solution :

The given equation of the circle is in the form of

x2 + y2 = r2

So, the center of the given circle is (0, 0).

Radius :.

r2 = 25

r = 5 units

Example 2 :

(x - 1)2 + (y - 3)2 = 9

Solution :

The given equation of the circle is in the form of

(x - h)2 + (y - k)2 = r2

Center :

(h, k) = (0, 0)

Radius :.

r= 9

r = 3 units

Example 3 :

(x + 3)2 + (y - 5)2 = 15

Solution :

The given equation of the circle is in the form of

(x - h)2 + (y - k)2 = r2

Center :

(h, k) = (-3, 5)

Radius :.

r= 15

r = √15 units

Example 4 :

x2 + y2  - 4x  - 6y + 9 = 0

Solution :

The given equation of circle is in general form.

Comparing 

x2 + y2 - 4x - 6y + 9 = 0

and 

x2 + y2 + 2gx + 2fy + c = 0

we get

2g = -4 ----> g = -2 ----> -g = 2

2f = -6 ----> f = -3 ----> -f = 3

Center :

(-g, -f) = (2, 3)

Radius :

r = √(g2 + f2 - c)

= √(4 + 9 - 9)

= √4

= 2 units

Example 5 :

Find the center of the circle described on the line joining the points (1, 2) and (2, 4) as its diameter.

Solution :

Center of the circle = Midpoint of the diameter

Substitute (x1, y1) = (1, 2) and (x2, y2) = (2, 4).

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