HOW TO FIND THE INDICATED TERM FROM THE GIVEN NTH TERM OF A SEQUENCE

To find the indicated term of a sequence, substitute the given value for n. 

For example, if you want to find 5th term of a sequence, substitute n = 5 in the nth term of the sequence.

Example 1 :

Find the indicated terms in each of the sequences whose nth terms are given by

an  =  (n + 2)/(2n + 3);     a7 and a9

Solution :

In order to find 7th term and 9th term, we have to apply 7 and 9 instead of n in the given nth term of the sequence.

7th term

an  =  (n + 2)/(2n + 3)

n = 7

a7  =  (7 + 2)/(2(7) + 3)

a7  =  9/(14 + 3)

a7  =  9/17

9th term

an  =  (n + 2)/(2n + 3)

n = 9

a9  =  (9 + 2)/(2(9) + 3)

a9  =  11/(18 + 3)

a9  =  11/21

Example 2 :

Find the indicated terms in each of the sequences whose nth terms are given by

an  =  (-1)n 2n + 3(n + 1);     a5 and a8

Solution :

In order to find 5th term and 8th term, we have to apply 5 and 8 instead of n in the given nth term of the sequence.

5th term

an  =  (-1)n 2n + 3(n + 1)

n = 5

a5  =  (-1)5 25 + 3(5+1)

a7  =  -1 ⋅ 28⋅ (6)

a7  =  -1 ⋅ (256)⋅ (6)

a7  =  - 1536

8th term

an  =  (-1)n 2n + 3(n + 1)

n  =  8

a8  =  (-1)8 28 + 3(8+1)

=  1 ⋅ 211 ⋅ (9)

a8  =  ⋅ (2048) ⋅ (9)

a8  =  18432

Example 3 :

Find the indicated terms in each of the sequences whose nth terms are given by

an  =  2n2 - 3n + 1;  a5 and a7

Solution :

In order to find 5th term and 7th term, we have to apply 5 and 7 instead of n in the given nth term of the sequence.

5th term

an  =  2n2 - 3n + 1

n = 5

a5  =  2n2 - 3n + 1

a5  =  2(5)2 - 3(5) + 1

a5  =  2(25) - 15 + 1

a5  =  50 - 15 + 1

a5  =  51 - 15

a5  =  36

7th term

an  =  (-1)n 2n + 3(n + 1)

n  =  8

a7  =  2n2 - 3n + 1

a7  =  2(7)2 - 3(7) + 1

a7  =  2(49) - 21 + 1

a7  =  98 - 21 + 1

a7  =  99 - 21

=  78

Example 4 :

Find the indicated terms in each of the sequences whose nth terms are given by

an  =  (-1)n (1 - n + n2);  a5 and a8

Solution :

In order to find 5th term and 8th term, we have to apply 5 and 8 instead of n in the given nth term of the sequence.

5th term

an  =  (-1)n (1 - n + n2)

n = 5

an  =  (-1)5 (1 - 5 + 52)

a5  =  (-1)(1 - 5 + 25)

a5  =  (-1)(26 - 5)

a5  =  -21

8th term

an  =  (-1)n (1 - n + n2)

n = 8

an  =  (-1)8 (1 - 8 + 82)

a8  =  1 (1 - 8 + 64)

a8  =  (65 - 8)

a8  =  57

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