In this online Aptitude Test 5,we give the questions whose qualities are in high standard and practicing these questions will definitely make the students to reach their goals.
Explanation
Question No.1 Question No.2 Question No.3 Question No.4 Question No.5 Question No.6 Question No.7 Question No.8 Question No.9 Question No.10 |
For each divisor and corresponding remainder, we have to find the difference.
35-25=10 45-35=10 55-45=10 we get the difference 10 (for all divisors and corresponding remainders) Now we have to find the L.C.M of (35,45,55) and subtract the difference from the L.C.M. L.C.M of (35,45,55) = 3465 Hence the required least number = 3465-10 = 3455
Let "x" be the length of each train
Total distance covered to cross each other = Sum of the lengths of the two trains Total distance covered to cross each other = x+x =2x m Relative speeds of the two trains = 46-36 = 10 kmph = 10X5/18 = 25/9 m/sec Distance = Speed X Time 2x = (25/9)X36 m 2x = 100 m x = 50 m Hence, the length of each train is 50 m
Total work = 60 units. (L.C.M of 10,15,20)
work done by the pipe A = 60/10 = 6 units/hr work done by the pipe B = 60/15 = 4 units/hr work done by the pipe C = 60/20 = 3 units/hr (Given:A is open all the time,B and C are open for one hour each alternately) 1st hour: (A+B) = 10 units/hr 2nd hour: (A+C) = 9 units/hr 3rd hour: (A+B) = 10 units/hr 4th hour: (A+C) = 9 units/hr 5th hour: (A+B) = 10 units/hr 6th hour: (A+C) = 9 units/hr When we add the above units, we get the total 57 units. Apart from the 6 hours of operation, to get the total work 60 units, A has to work for half an hour Because in one of hour work of A, we will get 6 units) Hence, time taken to fill the tank = 6.5 hours.
Let "x" be the speed of A . Then speed of B = 7-x
Time taken by A = 24/x Time taken by B = 24/(7-x) Time(A)+Time(B) = 14 hours. 24/x + 24/(7-x) = 14 24(7-x)+24x = 14x(7-x) 14x^{2}-98x+168=0--->x^{2}-7x+12=0 (x-4)(x-3)=0--->x = 4 and x = 3 Hence, the speed of A and B are 4 kmph and 3 kmph respectively.
From the given information, we have P+Q = 12+Q+R
When we rearrange the above equation, we get P-R = 12+Q-Q P-R = 12 From the above equation, it is very clear that R is 12 years younger to P
Let "x" be the average after 17th inning
(Total run scored in 17 innings)/17 = x Total run scored in 17 innings = 17x ----(1) Average after 16th inning = x-3 (Total run scored in 16 innings)/16 = x-3 Total runs scored in 16 innings = 16(x-3) Total runs scored in 17 innings = 16(x-3)+87 ----(2) From (1) and (2), we get 16(x-3)+87 = 17x Solving the above equation, we get x = 39 Hence the batsman's average after 17th inning is 39.
Let "x" be the speed of the current
Speed upstream = (10-x) kmph Speed downstream = (10+x) kmph From the given information, we have 26/(10+x) = 14/(10-x) 26(10-x) = 14(10+x) 260-26x = 140+14x 40x = 120 x = 120/40 = 3 kmhr Hence the speed of the current is 3 kmph
From the given information,
original of the 1st house = 16x original of the 2nd house = 23x After increment in prices, price of the 1st house = 16x + 10%of16x=16x+1.6x = 17.6x price of the 2nd house = 23x+477 After increment in prices, the ratio of the prices becomes 11:20 Then we have, 17.6x:(23x+477) = 11:20 20(17.6x) = 11(23x+477) 352x = 253x + 5247 99x = 5247 x = 53 Hence original price of the first house = 16X53 = $848
From the given information, we have
Profit on the first part (c) = 8% Profit on the second part (d) = 18% Profit on the whole (mixture) (m) = 14% Rule to find the ratio for producing mixture = (d-m):(m-c) (d-m):(m-c) = (18-14):(14-8) = 4:6 = 2:3 Quantity of the 2nd kind = 1000X3/5 = 600 kg The quantity sold at 18% profit is 600 kg
Let "x" be the price of a chair. Then the price of a table = x+400
4 tables + 6 chairs = 3600 4(x+400) + 6x = 3600 4x+1600+6x = 3600 10x = 2000 ===>x = 200 So, price of a chair = $400 and price of a table = $800 Price of a chair is $400 less than that of the table Percentage = (400/800)X100% = 50% Hence, the price of a chair is 50% less than that of the table. |