(a+b)3 = a3+3a2b+3ab2+b3
Problem 1 :
Expand (3x + 2y)3
(A) 27x³ + 9 x² y + 4 x y² + 8 y³
(B) 27x³ + 54 x² y + 16 xy² + 8 y³
(C) 9x2 + 24 xy + 9y²
Problem 2 :
Expand (2a + b)³
(A) 8a³ + 12 a² b + 6a b² + b ³
(B) 27a³ + 27 a² b + 16 ab² + b³
(C) 25a² + 24 a²b + 12 ab² + 9b²
Problem 3 :
Expand (S + T) ³
(A) S³ - 3 S² T + 3 ST ² + T ³
(B) S³ - 3 S² T - 3 S T ² + T ³
(C) S³ + 3 S² T + 3 S T ² + T ³
Problem 4 :
Expand (3V + Q) ³
(A) 27 V ³ + 2 V ² Q + 3 V Q² + Q³
(B) 27V³ - 2 V ² Q - 3 V Q² + Q³
(C) 27 V³ - 2 V²Q - 3V Q² + Q³
Problem 5 :
Expand (4T + 3Q) ³
(A) 64T³ - 96 T² Q - 108 T Q² + Q³
(B) 64T³ - 96 T² Q + 108 T Q² - Q³
(C) 64T³ + 96 T²Q + 108 T Q² + 27Q³
Problem 6 :
Expand (p + 5q)3
(A) p³ - 15 p² q + 75 p q² - 125 q³
(B) p³ - 15 p² q + 75 p q² + 125 q³
(C) p³ + 15 p² q + 75 p q² + 125 q³
Problem 1 :
Expand (3x + 2y)3
Solution :
Here a = 3x and b = 2y
(3x + 2y)3 = (3x)3 + 3(3x)2(2y) + 3(3x)(2y)2 + (2y)3
= 33x3 + 3 (9x 2) (2y) + 3 (3x) (4y2) + 8y3
= 27 x3 + 54 x 2y + 36 y2 + 8y3
Problem 2 :
Expand (2a + b)³
Solution :
Here a = 2a and b = b
(2a + b)3 = (2a)3 + 3 (2a) 2 (b) + 3 (2a) (b)2 + (b)3
= 23(a3) + 3 (4a) (b) + 3 (2a) (b)2 + (b)3
= 8a3 + 12 a b + 6 a b2 + b3
Problem 3 :
Expand (S + T)3
Solution :
Here a = S and b = T
(S + T)3 = S3 + 3 S2 T + 3 ST2 + T3
Problem 4 :
Expand (3V + Q)³
Solution :
Here a = 3V and b = Q
(3V + Q)3 = (3V)3 + 3 (3V) 2 (Q) + 3 (3V) (Q)2 + (Q)3
= 33V3 + 3(9V2)(Q) + 3 (3V) (Q)2 + (Q)3
= 27V3 + 27 V 2Q + 9 VQ2 + Q3
Problem 5 :
Expand (4T + 3Q) ³
Solution :
here a = 4T and b = 3Q
(4T + 3Q)3 = (4T)3 + 3(4T)2 (3Q) + 3(4T)(3Q)2 + (3Q)3
= 43T3 + 3 (16 T 2) (3Q) + 3 (4T) (9Q2) + 33Q3
= 64 T3 + 144 T 2 Q + 108 2 + 27 Q3
Problem 6 :
Expand (p + 5q)3
Solution :
here a = p and b = 5q
(p + 5q)3 = p3 + 3p2 (5q) + 3p(5q)2 + (5q)3
= p3 + 3 p2 (5q) + 3 p (25q2) + (53q3)
= p3 + 15 p 2 q + 75 p q2) + 125q3
Apart from the stuff given above, if you need any other stuff in math, please use our google custom search here.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Mar 19, 24 12:35 AM
Mar 18, 24 01:00 PM
Mar 18, 24 12:46 PM