ACT Practice Paper1 Solution1

In this page ACT practice paper1 solution1 we are going to see solution of some practice questions.

Question 1:

If x = -2 and y = 3 then find the value of |2 x - 3 y|

Solution:

To find the value of |2 x - 3 y| we have to apply the value of x and y in the given statement.

                 = |2 x - 3 y|

                 = |2 (-2) - 3 (3)|

                 = |-4 - 9|

                 = |-13|

                 = 13

So the required answer 13.


Question 2:

Simplify the following (8 + 5) x (35/5) + 6

Solution:

To simplify this we have to use the rule known as "BODMAS" in the topic "order of operation". First we have to consider the symbol bracket or parenthesis.

                 = (8 + 5) x (35/5) + 6

                 = 13 x 7 + 6

next we have to multiply

                 = 91 + 6     

finally we have to add

                 = 97

So the required answer will be 97.


Question 3:

54 _562. This number is divisible by 3. Fill in the blank with any least suitable digit.

Solution:

Here the given number 54 _562 is divisible by 3. From this we have to fill a suitable number. For that let us remember the condition for a number which is divisible by 3. 

Definition:

A number is divisible by 3 if the sum of the digits is divisible by 3.Ex : 363 Here sum of the digits 3 + 6 + 3 = 9 which is divisible by 3.So the whole number will be divisible by 3.

Let us consider the missing number as "x". Let us find the sum of digits

                 = 5 + 4 + x + 5 + 6 + 2

                 = 9 + x + 11 + 2

                 = 22 + x

There is only one number should be placed. If we put 2 instead of x, the sum will become 24. So it will be divisible by 3. If we put 5 instead of x, the sum will become 27. That number also be divided by 3.But we have to put only least number. So we have to choose 2.


Question 4:

The weight of an empty bottle is 128.4 gram. It contains a syrup. The weight of the syrup is 156.8 gram. What is the weight of 24 bottles of syrup?

Solution:

The weight of an empty bottle = 128.4 gram

weight of the syrup = 156.8 gram

weight of one bottle with syrup = weight of empty bottle + weight of syrup

                                              = 128.4 + 156.8

                                              = 285.2

from this we have to find the weight of 24 bottles

                                              = 24 x 285.2

                                              = 6844.8 grams

So the required weight is 6844.8 grams

ACT practice paper1 solution1  ACT practice paper1 solution1