Problem 1 :
Arrange the following digits so that they make smallest possible number.
8, 4, 5, 9, 7, 6, 1, 3, 2
(A) 142356789 (B) 132456789 (C) 123456789
Solution :
The smallest possible number that can be formed by the given digits.
123456789
Problem 2 :
Write the number that is 1000 more than 636272
(A) 637212 (B) 637272 (C) 632714
Solution :
636272 + 1000 = 637272
Problem 3 :
Write the roman numeral for XXVIII
(A) 42 (B) 28 (C) 36
Solution :
Roman numeral for XXVIII is 28.
Problem 4 :
Fill in the blank with the biggest digit possible.
764 _ 28.This number is divisible by 9.
(A) 3 (B) 9 (C) 7
Solution :
Let x be the unknown
7 + 6 + 4 + x + 2 + 8 = 27 + x
If x is 9, we get 36 and it is divisible by 9.
So, the answer is 9.
Problem 5 :
A number which does not have a factor other than the number itself and 1, is called _______________ number.
(A) Prime (B) Composite (C) None of these
Solution :
The number which does not have a factor other than 1 and itself is known as prime number.
Problem 6 :
The number which divides another number and gives no remainders is a ____________ of that number.
(A) divisor (B) factor (C) none of these
Solution :
For example, let us divide 6 by 2. We get 3 as quotient and 0 as remainder.
So, 2 is the factor of 6.
Problem 7 :
Find the HCF of 96 and 120.
(A) 24 (B) 35 (C) 12
Solution :
= 2 ⋅ 2 ⋅ 2 ⋅ 3
= 24
So, the highest common factor is 24.
Problem 8 :
Find the value of 56.725 + 48.258 - 32.564
(A) 148.63 (B) 59.478 (C) 72.419
Solution :
56.725 + 48.258 ==> 104.983
104.983 - 32.564 ==> 72.419
Problem 9 :
In an Army camp provisions were there for 500 men for 28 days . If 400 men attended the camp, then how long did the provisions last ?
(A) 35 days (B) 10 days (C) 50 days
Solution :
Number of men came to provision = 550
Number of days did it run = 28
Total contextion = 550 ⋅ 28 = 15400
If, number of men have come to the provision = 700
Then, number of days will it run = 15400 / 700
= 22 days.
If 700 men would have come, then the provision would have run for 22 days.
Problem 10 :
Find the number of days from November 10ᵗʰ 1997 to April 15ᵗʰ 1998.
(A) 85 days (B) 156 days (C) 79 days
Solution :
November = 31 - 10 ==> 21
December = 30
January = 31
February = 28
March = 31
April = 15
= 21+ 30 + 31 + 28 + 31 + 15
= 156 days
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