This page 10th cbse maths solution for exercise 3.3 is going to provide you solution for every problems that you find in the exercise no 3.3

(1) Solve the following pair of linear equations by the substitution method.

(i) x + y = 14

x - y = 4 **Solution**

(ii) s - t = 3

(s/3) + (t/2) = 6 **Solution**

(iii) 3 x - y = 3

9 x - 3 y = 9 **Solution**

(iv) 0.2 x + 0.3 y = 1.3

0.4 x + 0.5 y = 2.3 **Solution**

(v) √2 x + √3y =0

√3 x - √8 y = 0 **Solution**

(vi) (3x/2) - (5y/3) = -2

(x/3) + (y/2) = 13/6 **Solution**

(2) Solve 2 x + 3 y = 11 and 2 x - 4 y = -24 and hence find the value of "m" fir which y = m x + 3 **Solution**

(3) Form the pair of linear equations of the following problems and find their solution by substitution method.

(i) The difference between two numbers is 26 and one number is three times the other. Find them **Solution**

(ii) The larger of two supplementary angles exceeds the smaller by 18 degrees. Find them **Solution**

(iii) The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later,she buys 3 bats and 5 balls for Rs.1750. Find the cost if each bat and each ball. **Solution**

(iv) The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km,the charge paid is Rs.105 and for a journey of 15 km,the charge paid is Rs 155. What are the fixed charge and charge per km? How much does a person have to pay for traveling a distance of 25 km? **Solution**

(v) A fraction becomes 9/11,if 2 is added to both numerator and the denominator.If 3 is added to both the numerator and denominator it becomes 5/6. Find the fraction. **Solution**

(vi) Five years hence, the age of Jacob will be three times that of his son.Five years age,Jacob's age was seven times that of his son. What are their present age? **Solution**

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