This page 10th CBSE math solution for exercise 5.1 part 2 is going to provide you solution for every problems that you find in the exercise no 5.1 part 2

(2) Write first four terms of the A.P when the first term a and common difference d are given as follows.

(i) a = 1 0 d = 10

Solution:

First term (a₁**) = 10**

**Second term (a₂) = a + d**

** = 10 + 10 **

** = 20**

**Third term (a****₃) = a + 2d**

** = 10 + 2(10) **

** = 10 + 20 **

** = 30**

**Fourth term (a****₄) = a + 3d**

** = 10 + 3(10) **

** = 10 + 30 **

** = 40**

**Therefore the first four terms are 10,20,30 and 40**

(ii) a = -2 d = 0

Solution:

First term (a₁**) = -2**

**Second term (a₂) = a + d**

** = -2 + 0 **

** = -2**

**Third term (a****₃) = a + 2d**

** = -2 + 2(0) **

** = -2 + 0 **

** = -2**

**Fourth term (a****₄) = a + 3d**

** = -2 + 3(0) **

** = -2 + 0 **

** = -2**

**Therefore the first four terms are -2,-2,-2 and -2**

(iii) a = 4 d = -3

Solution:

First term (a₁**) = 4**

**Second term (a₂) = a + d**

** = 4 + (-3) **

** = 1**

**Third term (a****₃) = a + 2d**

** = 4 + 2(-3) **

** = 4 - 6 **

** = -2**

**Fourth term (a****₄) = a + 3d**

** = 4 + 3(-3) **

** = 4 - 9 **

** = -5**

**Therefore the first four terms are 4,1,-2 and -5**

(iv) a = -1 d = 1/2

Solution:

First term (a₁**) = -1**

**Second term (a₂) = a + d**

** = -1 + (1/2) **

** = -1/2**

**Third term (a****₃) = a + 2d**

** = -1 + 2(1/2) **

** = -1 + 1 **

** = 0**

**Fourth term (a****₄) = a + 3d**

** = -1 + 3(1/2) **

** = -1 + (3/2) **

** = 1/2**

**Therefore the first four terms are -1,-1/2,0 and 1/2**

(v) a = - 1.25 d = -0.25

Solution:

First term (a₁**) = -1.25**

**Second term (a₂) = a + d**

** = -1.25 + (-0.25) **

** = -1.25 - 0.25**

** = -1.50 **

**Third term (a****₃) = a + 2d**

** = -1.25 + 2(-0.25) **

** = -1.25 - 0.50 **

** = -1.75**

**Fourth term (a****₄) = a + 3d**

** = -1.25 + 3(-0.25) **

** = -1.25 - 0.75 **

** = 2**

**Therefore the first four terms are -1.25,-1.50,-1.75 and 2**

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