10th CBSE math solution for exercise 5.1 part 2

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10th CBSE math solution for exercise 5.1 part 2

(2) Write first four terms of the A.P when the first term a and common difference d are given as follows.

(i) a = 1 0  d = 10

Solution:

First term (a) = 10

Second term (a₂) = a + d

                   = 10 + 10

                   = 20

Third term (a₃) = a + 2d

                 = 10 + 2(10)

                 = 10 + 20

                 = 30

Fourth term (a₄) = a + 3d

                 = 10 + 3(10)

                 = 10 + 30

                 = 40

Therefore the first four terms are 10,20,30 and 40


(ii) a = -2  d = 0

Solution:

First term (a) = -2

Second term (a₂) = a + d

                   = -2 + 0 

                   = -2

Third term (a₃) = a + 2d

                 = -2 + 2(0)

                 = -2 + 0

                 = -2

Fourth term (a₄) = a + 3d

                 = -2 + 3(0)

                 = -2 + 0

                 = -2

Therefore the first four terms are -2,-2,-2 and -2


(iii) a = 4  d = -3

Solution:

First term (a) = 4

Second term (a₂) = a + d

                   = 4 + (-3)

                   = 1

Third term (a₃) = a + 2d

                 = 4 + 2(-3)

                 = 4 - 6

                 = -2

Fourth term (a₄) = a + 3d

                 = 4 + 3(-3)

                 = 4 - 9

                 = -5

Therefore the first four terms are 4,1,-2 and -5


(iv) a = -1  d = 1/2

Solution:

First term (a) = -1

Second term (a₂) = a + d

                   = -1 + (1/2)

                   = -1/2

Third term (a₃) = a + 2d

                 = -1 + 2(1/2)

                 = -1 + 1

                 = 0

Fourth term (a₄) = a + 3d

                 = -1 + 3(1/2)

                 = -1 + (3/2)

                 = 1/2

Therefore the first four terms are -1,-1/2,0 and 1/2


(v) a = - 1.25   d = -0.25

Solution:

First term (a) = -1.25

Second term (a₂) = a + d

                   = -1.25 + (-0.25)

                   = -1.25 - 0.25

                   = -1.50  

Third term (a₃) = a + 2d

                 = -1.25 + 2(-0.25)

                 = -1.25 - 0.50

                 = -1.75

Fourth term (a₄) = a + 3d

                 = -1.25 + 3(-0.25)

                 = -1.25 - 0.75

                 = 2

Therefore the first four terms are -1.25,-1.50,-1.75 and 2




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