10th CBSE math solution for exercise 2.2 part 3

This page 10th CBSE math solution for exercise 2.2 part 3 is going to provide you solution for every problems that you find in the exercise no 2.2

10th CBSE math solution for exercise 2.2 part 3

(iv)  1, 1

Solution:

α = 1

 β = 1

General form of a quadratic equation

x² – (α + β) x + α β = 0

α + β = 1 + 1

          = 2

α β = (1) (1)

        = 1

  x² – 2 x + 1 = 0


(v)  -1/4, 1/4

Solution:

α = -1/4

 β = 1/4

General form of a quadratic equation

x² – (α + β) x + α β = 0

α + β = -1/4 + 1/4

          = 0

α β = (-1/4) (1/4)

        = -1/16

  x² – 0 x + (-1/16) = 0

16 x² – 1 = 0


(vi) 4, 1

Solution:

α = 4

 β = 1

General form of a quadratic equation

x² – (α + β) x + α β = 0

α + β = 4 + 1

          = 5

α β = 4 (1)

        = 4

  x² – 5 x + 4 = 0

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